A radioactive decay forms an isotope of the original nucleus with the emission of the following particles
A radioactive decay forms an isotope of the original nucleus with the emission of the following particles
one $\alpha$ - and four $\beta$-particles
one $\alpha$ - and one $\beta$-particles
one $\alpha$ - and two $\beta$-particles
four $\alpha$ - and one $\beta$-particles
Solution
Isotopes are those atoms which have same atomic number and difference mass number
${ }_{\mathrm{z}}^{\mathrm{A}} \mathrm{X} \rightarrow \mathrm{z}_{\mathrm{Z}} \mathrm{Y}^{\mathrm{A}}+\alpha+2 \beta$
Hence $1 \alpha$ and $2 \beta$ particles will emit for the decay of isotope.