A quadrilateral has area $84 \text{ cm}^{2}$. One diagonal is $14$ cm. If one of the perpendiculars from a…

A quadrilateral has area $84 \text{ cm}^{2}$. One diagonal is $14$ cm. If one of the perpendiculars from a vertex to this diagonal is $5$ cm, find the other perpendicular.
  1. $5$ cm
  2. $7$ cm
  3. $8$ cm
  4. $12$ cm

Solution

$\dfrac{1}{2}\times 14 (5 + h_{2}) = 84 \Rightarrow 7(5+h_{2}) = 84 \Rightarrow 5+h_{2} = 12 \Rightarrow h_{2} = 7$ cm.

Asked in: IMO

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