A proton moving in perpendicular magnetic field possess energy $E$. The strength of magnetic field is increases four times. But the proton is constrained to move in the path of same radius. The kinetic energy of proton will increase

Question

Aicharya · Accepted Answer

$r=\frac{\mathrm{mv}}{q B}=\frac{\sqrt[2]{2 m E}}{q B} E \propto B^2$ If $B$ increases 4 times $E$ becomes to 16 times

A proton moving in perpendicular magnetic field possess energy $E$. The strength of magnetic field is…

Solution