A proton and an alpha particle both enter a region of uniform magnetic field B, moving at right angles to…

A proton and an alpha particle both enter a region of uniform magnetic field B, moving at right angles to the field B. if the radius of circular orbits for both the particles is equal and the kinetic energy acquired by proton is 1 MeV, the energy acquired by the alpha particle will be:
  1. 0.5 MeV
  2. 1..5 MeV
  3. 1 MeV
  4. 4 MeV

Solution

R=mVqB=2mkEqB
Since R is same so KE ∝q2m
So KE of α particle will be 224=1 MeV

Asked in: NEET 2015 (Phase 2)

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