A projectile is given an initial velocity of i ^ + 2 j ^   m   s - 1 , where i ^ is along the…

A projectile is given an initial velocity of i^+2j^ m s-1, where i ^ is along the ground and j ^ is along the vertical upward. If g=10 m s-2, the equation of its trajectory is :
  1. 4y=2x-5x2
  2. 4y=2x-25x2
  3. y=x-5x2
  4. y=2x-5x2

Solution

v → = i ^ + 2 j ^

⇒ x = t    ..... (i)

y = 2 t - 1 2 1 0 t 2    ..... (ii)

From (i) and (ii)

y = 2 x - 5 x 2

Asked in: JEE Main 2013 (07 Apr)

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