A projectile is fired with the velocity v 0 = 2 m s - 1 at an angle 60 o with horizontal. At top of its…

A projectile is fired with the velocity v0= 2 m s-1 at an angle 60o with horizontal. At top of its trajectory, it explodes into three fragments of equal mass. The first fragment retraces the path, second moves vertically upward with speed 3v02. The speed of the third fragment (in m s-1) is
 

Solution

Picture 73
Let velocity of third fragment be V
Pi=Pf
3mv02i^=mv02i^+m3v02j^+mv
v =4 v 0 2 i ^ 3 v 0 2 j ^
v=5v02 

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