A projectile is fired from the surface of the earth with a velocity of 5 m s - 1 and angle θ with the horizontal. Another projectile fired from another planet with a velocity of 3 m s - 1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the…

Question

A projectile is fired from the surface of the earth with a velocity of 5 m s - 1 and angle θ with the horizontal. Another projectile fired from another planet with a velocity of 3 m s - 1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is: (given g = 9.8 m s - 2 )

Aicharya · Accepted Answer

The Equation of the Trajectory of a Projectile y = x tan θ - g x 2 2 u 2 cos θ y, x are Variable and θ is constant so g u 2 = c o n s tan t g 5 2 = a 3 2 a = 9.8 × 9 25 a = 3.5

A projectile is fired from the surface of the earth with a velocity of 5 m s - 1 and angle θ with the…

Solution