A projectile can have the same range $\mathrm{R}$ for two angles of projection. If $\mathrm{t}_1$ and…

A projectile can have the same range $\mathrm{R}$ for two angles of projection. If $\mathrm{t}_1$ and $\mathrm{t}_2$ be the times of flights in the two cases, then the product of the two time of flights is proportional to
  1. $\mathrm{R}^2$
  2. $1 / R^2$
  3. $1 / \mathrm{R}$
  4. $\mathrm{R}$

Solution

$\mathrm{t}_1 \mathrm{t}_2=\frac{2 \mathrm{u}^2 \sin 2 \theta}{\mathrm{g}^2}=\frac{2 \mathrm{R}}{\mathrm{g}}$

Asked in: JEE Main 2005

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