A progressive wave of frequency $50 \mathrm{~Hz}$ is travelling with velocity $350 \mathrm{~m} / \mathrm{s}$…

A progressive wave of frequency $50 \mathrm{~Hz}$ is travelling with velocity $350 \mathrm{~m} / \mathrm{s}$ through a medium. The change in phase at a given time interval of 0.01 second is
  1. $\frac{\pi}{4} \mathrm{rad}$
  2. $\frac{3 \pi}{2} \mathrm{rad}$
  3. $\pi \mathrm{rad}$
  4. $\frac{\pi}{2} \mathrm{rad}$

Solution

$\begin{aligned} & \frac{\text { Phase Difference }}{2 \pi}=\frac{\text { Time Difference }}{\mathrm{T}} \\ & \Rightarrow \Delta \phi=\frac{2 \pi}{\mathrm{T}} \times \Delta \mathrm{t}=\frac{2 \pi}{1 / 50} \times 0.01=\pi \text { radian } \end{aligned}$ .

Asked in: MHT CET 2021 (21 Sep Shift 1)

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