A progressive wave of frequency 400 Hz is travelling with a velocity $336 \mathrm{~m} / \mathrm{s}$. How far apart are the two points which are $60^{\circ}$ out of phase?

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Aicharya · Accepted Answer

Phase difference $(\phi)=60^{\circ}$ or $\frac{\pi}{3} \mathrm{rad}$ $	herefore \quad$ Path difference $=\frac{\lambda}{2 \pi} 	imes \phi=\frac{\lambda}{2 \pi} 	imes \frac{\pi}{3}=\frac{\lambda}{6}$ $	herefore \quad$ Path difference $=\frac{\lambda}{6}=\frac{v}{n} 	imes \frac{1}{6} \quad \ldots(\because v=\mathrm{n} \lambda)$ Substituting given values, Path difference $=\frac{336}{400} 	imes \frac{1}{6}=0.14 \mathrm{~m}$

A progressive wave of frequency 400 Hz is travelling with a velocity $336 \mathrm{~m} / \mathrm{s}$. How far…

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