A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same…
A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of the ball) due to this charge is \(E\). Let us put a positive test charge \(q_{0}\) at this point and measure \(F / q_{0}\) on this charge. Then, \(E\)
\( > F / q_{0}\)
\( < F / q_{0}\)
\(=F / q_{0}\)
none of these
Solution
\(E=\frac{k Q}{r^{2}}\) (i)
\(F=\frac{k Q q_{0}}{r_{1}^{2}} \Rightarrow \frac{F}{q_{0}}=\frac{k Q}{r_{1}^{2}}\) (ii)
As \(r_{1} > r\), so from (i) and (ii) \(E > \frac{F}{q_{0}}\)
Asked in: JEE Mains - Electrostatics - Chapter Test
