A positive point charge is released from rest at a distance r 0 from a positive line charge with uniform…

A positive point charge is released from rest at a distance ${\mathrm{r}}_0$ from a positive line charge with uniform charge density. The speed $\left(\mathrm{v}\right)$ of the point charge, as a function of instantaneous distance $\mathrm{r}$ from line charge, is proportional to

1. $\mathrm{v}\propto \left(\frac{\mathrm{r}}{{\mathrm{r}}_0}\right)$
2. $\mathrm{v}\propto \sqrt{\ln \left(\frac{\mathrm{r}}{{\mathrm{r}}_0}\right)}$
3. $\mathrm{v}\propto \ln \left(\frac{\mathrm{r}}{{\mathrm{r}}_0}\right)$
4. $\mathrm{v}\propto {\mathrm{e}}^{\raisebox{1ex}{$+\mathrm{r}$}\!\left/ \!\raisebox{-1ex}{${\mathrm{r}}_0$}\right.}$

Solution

Asked in: JEE Main 2019 (08 Apr Shift 2)

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