A positive ion $A$ and a negative ion $B$ has charges $6.67 \times 10^{-19} \mathrm{C}$ and $9.6 \times…
(Take $\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-1}$ and universal gravitational constant as $6.67 \times 10^{-11} \mathrm{Nm}^2 \mathrm{~kg}^{-2}$)
Assume that charge may not be an integral multiple of electrons.
Solution
F_e & =\frac{k q_1 q_2}{r^2} \\ F_g & =\frac{G m_1 m_2}{r^2} \\ \frac{F_e}{F_g} & =\frac{k q_1 q_2}{G m_1 m_2} \\ & =\frac{9 \times 10^9 \times 6.67 \times 10^{-19} \times 9.6 \times 10^{-10}}{6.67 \times 10^{-11} \times 19.2 \times 10^{-27} \times 9 \times 10^{-27}} \\ & =\frac{10^{-20}}{2 \times 10^{-65}}
\end{aligned}$
Asked in: JEE Main 2025 (23 Jan Shift 1)