A positive charge q is given to each plate of a parallel plate air capacitor having plate area A and plate…

A positive charge q is given to each plate of a parallel plate air capacitor having plate area A and plate separation d, then
  1. since both the plates are identically charged, therefore, capacitance becomes equal to zero
  2. energy stored in the space between the capacitor plates is equal to q2ε0A2
  3. no charge appears on inner surface of the plates
  4. potential difference between the plates is equal to 2qdε0A

Solution

Capacitance does not depend on charge on it, C=ε0Ad



In final charge distribution, Charge on outer plates q1=q4=q and inner plates q2=q3=0

As charge on inner plates are zero so there is no field between the plates and no potential difference and no energy is stored.

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Asked in: JEE Mains - Capacitance - Test 1

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