A polygon has 44 diagonals. Then the number of sides of the polygon are

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Aicharya · Accepted Answer

Number of diagonals of ' $n$ ' sided polygons $={ }^n C_2-n$ $\begin{aligned} & 	herefore{ }^n C_2-n=44 \ & \frac{n !}{2 !(n-2) !}-n=44 \Rightarrow n(n-1)-2 n=88 \ & 	herefore n^2-3 n-88=0 \Rightarrow(n-11)(n+8)=0 \ & \Rightarrow n=11 \ldots[n \in N] \end{aligned}$

A polygon has 44 diagonals. Then the number of sides of the polygon are

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