A polyatomic gas $\left(Y=\frac{4}{3}\right)$ is compressed to $\left(\frac{1}{8}\right)^{\text {th }}$ of…
A polyatomic gas $\left(Y=\frac{4}{3}\right)$ is compressed to $\left(\frac{1}{8}\right)^{\text {th }}$ of its volume adiabatically. If its initial pressure is $p$, its new pressure will be
8p
16p
2p
6p
Solution
For an adiabatic process: $p V \gamma=$ constant
Let initial pressure be $p$ and volume $V$, then the final pressure is $P$
and volume $\frac{V}{8}$.
$\begin{aligned}
& \Rightarrow p V^{4 / 3}=P\left(\frac{V}{8}\right)^{4 / 3} \\
& \Rightarrow P=8^{4 / 3} p=16 p
\end{aligned}$