A point P consider at the contact point of a wheel on the ground which roll on the ground without slipping, then the value of the displacement of point $\mathrm{P}$ when wheel completes half of the rotation (if radius of wheel is $1 \mathrm{~m}$ )is:

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Aicharya · Accepted Answer

Displacement $P Q$ $\begin{aligned} & =\sqrt{(P M)^2+(Q M)^2} \ & =\sqrt{(\pi R)^2+(2 R)^2} \ & =\sqrt{\pi^2+4}\{\because R=1 \mathrm{~m}\} \end{aligned}$

A point P consider at the contact point of a wheel on the ground which roll on the ground without slipping,…

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