A point lies $5$ units above the $x$-axis on the $y$-axis. Its perpendicular distance from the $x$-axis…
A point lies $5$ units above the $x$-axis on the $y$-axis. Its perpendicular distance from the $x$-axis equals:
- $0$
- $5$
- $2.5$
- Cannot be determined
Solution
Such a point is $(0,5)$. Distance from the $x$-axis is $|y|=5$.
Asked in: IMO
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