A point is moving on $y=4-2 x^2$. The $x$-coordinate of the point is decreasing at the rate of 5…

A point is moving on $y=4-2 x^2$. The $x$-coordinate of the point is decreasing at the rate of 5 units/second. Then, the rate at which $y$ coordinate of the point is changing when the point is at $(1,2)$ is
  1. 5 unit/s
  2. 10 unit/s
  3. 15 unit/s
  4. 20 unit/s

Solution

Given equation of curve is $ y=4-2 x^2 $ On differentiating both sides w.r.t. $t$, we get $ \begin{aligned} \frac{d y}{d t} & =-4 x \frac{d x}{d t} \\ \because \quad \frac{d x}{d t} & =-5, \text { point }(1,2) \\ \Rightarrow \quad \frac{d y}{d t} & =-4(1)(-5)=20 \text { unit/s } \end{aligned} $

Asked in: AP EAMCET 2004

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