A point charge ' $q$ ' coulomb is placed at the centre of a cube of side length ' $L$ '. Then the electric…
A point charge ' $q$ ' coulomb is placed at the centre of a cube of side length ' $L$ '. Then the electric flux linked with each face of the cube is
- $\frac{q}{\epsilon_0}$
- $\frac{q}{L^2 \in_0}$
- $\frac{q}{6 L^2 \epsilon_0}$
- $\frac{q}{6 \epsilon_0}$
Solution
By Gauss's theorem, electric flux, $\phi_{\text {cube }}=\frac{\mathrm{Q}_{\text {in }}}{\varepsilon_0}=\frac{\mathrm{q}}{\varepsilon_0} \Rightarrow 6 \phi_{\text {face }}=\frac{\mathrm{q}}{\varepsilon_0}$ $\therefore \phi_{\text {face }}=\frac{q}{6 \varepsilon_0}$
Asked in: AP EAMCET 2024 (21 May Shift 1)
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