A point charge 2 × 10 – 2   C is moved from P to S in a uniform electric field of 30  …

A point charge 2×102 C is moved from P to S in a uniform electric field of 30 N C1 directed along positive x-axis. If coordinates of P and S are (1, 2, 0) m and (0, 0, 0) m respectively, the work done by electric field will be
  1. 1200 mJ
  2. 600 mJ
  3. -600 mJ
  4. -1200 mJ

Solution

As electric field is uniform, so force acting on the charged particle will be uniform.

Therefore,

WE=F·s=qE·s

=2×10-230i^·0i^+0j^+0k^-i^+2j^+0k^

=-60×10-2 J

=-600 mJ

Asked in: JEE Main 2023 (29 Jan Shift 2)

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