A player tosses 2 fair coins. He with Rs. 5 if 2 heads appear, Rs. 2 if 1 head appears and Rs. 1 if no head…
- $\frac{9}{4}$
- 6
- $\frac{5}{2}$
- $\frac{17}{2}$
Solution
Variance $=\sum p_i x_i{ }^2-\left(\sum p_i x_i\right)^2$
$=\frac{17}{2}-\frac{25}{4}=\frac{9}{4}$Asked in: MHT CET 2022 (08 Aug Shift 1)