A plane is inclined at an angle α = 30 ° with respect to the horizontal. A particle is projected…

A plane is inclined at an angle $\mathrm{\alpha }=30°$ with respect to the horizontal. A particle is projected with a speed $\mathrm{u}=2\mathrm{ }\mathrm{m}\mathrm{ }{\mathrm{s}}^{-1}$ , from the base of the plane, making an angle $\mathrm{\theta }=15°$ with respect to the plane as shown in the figure. The distance from the base, at which the particle hits the plane is close to:
(Take $\mathrm{g}=10\mathrm{ }\mathrm{m}\mathrm{ }{\mathrm{s}}^{-2}$ )

1. $20\mathrm{ }\mathrm{c}\mathrm{m}$
2. $18\mathrm{ }\mathrm{c}\mathrm{m}$
3. $14\mathrm{ }\mathrm{c}\mathrm{m}$
4. $26\mathrm{ }\mathrm{c}\mathrm{m}$

Solution

Asked in: JEE Main 2019 (10 Apr Shift 2)

Practice more Motion In Two Dimensions questions on Aicharya