A pipe $\mathrm{P}_{\mathrm{C}}$ closed at one end and pipe $\mathrm{P}_{\mathrm{O}}$ open at both ends are…

A pipe $\mathrm{P}_{\mathrm{C}}$ closed at one end and pipe $\mathrm{P}_{\mathrm{O}}$ open at both ends are vibrating in second overtone. They are in resonance with a given tuning fork. The ratio of the length of pipe $\mathrm{P}_{\mathrm{C}}$ vs $\mathrm{P}_{\mathrm{O}}$ is (Neglect end correction)
  1. $\frac{4}{5}$
  2. $\frac{5}{6}$
  3. $\frac{2}{3}$
  4. $\frac{3}{5}$

Solution

For second overtone: If they are in the resonance with the same tuning fork, using: $\lambda \mathrm{f}=\mathrm{v}$ $f$ and $v$ are the same, so $\begin{aligned} & \lambda_C=\lambda_0 \\ & \therefore\left(\frac{4}{5} L_C\right)=\frac{2}{3} L_0 \\ & \Rightarrow \frac{L_C}{L_0}=\frac{5}{6}\end{aligned}$

Asked in: MHT CET 2022 (05 Aug Shift 2)

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