A photograph of a landscape is captured by a drone camera at a height of 18 km. The size of the camera film…
- 1.8 cm
- 0.9 cm
- 2.8 cm
- 2.5 cm
Solution

$\mathrm{H}=18 \mathrm{~km}$
Size of camera film $=2 \mathrm{~cm} \times 2 \mathrm{~cm}$
$\begin{aligned}
& A_{\text {image }}=400 \mathrm{~km}^2 \\ & x=20 \times 10^3 \mathrm{~m}=2 \times 10^4 \mathrm{~m} \\ & y=2 \times 10^{-2} \mathrm{~m} \\ & \frac{x}{y}=10^6=\frac{18 \mathrm{Km}}{\mathrm{f}} \\ & \mathrm{f}=18 \times 10^{-3} \mathrm{~m}=18 \mathrm{~mm} \\ & \mathrm{f}=1.8 \mathrm{~cm}
\end{aligned}$
Asked in: JEE Main 2025 (24 Jan Shift 2)