A person throws two fair dice. He wins Rs. 15 for throwing a doublet (same numbers on the two dice), wins Rs…

A person throws two fair dice. He wins Rs. 15 for throwing a doublet (same numbers on the two dice), wins Rs 12 when the throw results in the sum of 9 , and loses Rs. 6 for any other outcome on the throw. Then the expected gain/loss (in Rs.) of the person is:
  1. 12 loss
  2. 12 gain
  3. 2 gain
  4. 14 loss

Solution

win Rs. 15→ number of cases =6
win Rs. 12→ number of cases  =4
loss Rs. 6→ number of cases =26
p (expected gain/loss)  =15×636+12×436-6×2636=-12

Asked in: JEE Main 2019 (12 Apr Shift 2)

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