A person of 80   kg mass is standing on the rim of a circular platform of mass 200   kg rotating…

A person of 80 kg mass is standing on the rim of a circular platform of mass 200 kg rotating about its axis at 5 revolutions per minute (rpm). The person now starts moving towards the centre of the platform. What will be the rotational speed (in rpm ) of the platform when the person reaches its centre....

Solution

Applying conservation of angular momentum,

mR2+MR22ω=MR22ω'

80+2002×5=2002ω'

ω'=9rev/sec.

Asked in: JEE Main 2020 (03 Sep Shift 1)

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