A person moves $30 \mathrm{~m}$ north and then $20 \mathrm{~m}$ towards east and finally $30 \sqrt{2}…
- $10 \mathrm{~m}$ along north
- $10 \mathrm{~m}$ along south
- $10 \mathrm{~m}$ along west
- zero
Solution
From figure, $\overrightarrow{O A}=0 \hat{i}+30 \hat{j}$
$\overrightarrow{A B}=20 \hat{i}+0 \vec{j}$
$\overrightarrow{B C}=-30 \sqrt{2} \cos 45^{\circ} \hat{i}-30 \sqrt{2} \sin 45^{\circ} \hat{j}$
$=-30 \hat{i}-30 \vec{j}$
$\therefore$ Net displacement, $\overrightarrow{O C}=\overrightarrow{O A}+\overrightarrow{A B}+\overrightarrow{B C}=-10 \hat{i}+0 \hat{j}$
$\overrightarrow{O C} \mid=10 \mathrm{~m}$ ^
Asked in: JEE Mains - Motion In One Dimension - Test 1