A perfect gas $(0.1 \mathrm{~mol})$ having $\overline{\mathrm{C}}_{\mathrm{v}}=1.50 \mathrm{R}$ (independent…


A perfect gas $(0.1 \mathrm{~mol})$ having $\overline{\mathrm{C}}_{\mathrm{v}}=1.50 \mathrm{R}$ (independent of temperature) undergoes the above transformation from point 1 to point 4. If each step is reversible, the total work done (w) while going from point 1 to point 4 is $(-)$ ________ J (nearest integer) $\left[\right.$ Given : $\left.\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right]$

Solution

$\begin{aligned}
& \mathrm{W}_{1 \rightarrow 2}=0 \\
& \mathrm{~W}_{2 \rightarrow 3}=-\mathrm{P} \Delta \mathrm{~V} \\
& =-3[2-1] \\
& =-3 \mathrm{~atm}-\ell
\end{aligned}$
$\mathrm{W}_{3 \rightarrow 4}=0$
Total work done
$\begin{aligned}
& =-3 \mathrm{~atm}-\ell \\
& =-3 \times 101.3 \text { Joule } \\
& =-304 \text { Joule }
\end{aligned}$

Asked in: JEE Main 2025 (03 Apr Shift 2)

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