A pendulum is oscillating at a frequency of $8 \mathrm{~Hz}$. Suddenly the string of the pendulum is clamped at its midpoint then the new frequency of oscillations is

Question

Aicharya · Accepted Answer

$\mathrm{f}=\frac{1}{2 \pi} \sqrt{\frac{\mathrm{g}}{\ell}}$ $\begin{aligned} & \mathrm{f} \propto \frac{1}{\sqrt{\ell}} \\ & \frac{\mathrm{f}_2}{\mathrm{f}_1}=\sqrt{\frac{\ell_1}{\ell_2}}=\sqrt{\frac{\ell \times 2}{\ell}} \\ & \mathrm{f}_2=\sqrt{2} \mathrm{f}_1=\sqrt{2} \times 8 \\ & =11.28 \mathrm{~Hz}\end{aligned}$

A pendulum is oscillating at a frequency of $8 \mathrm{~Hz}$. Suddenly the string of the pendulum is clamped…

Solution