A particle undergoes a one-dimensional motion such that its velocity varies according to v x = β x - 2 n ,…

A particle undergoes a one-dimensional motion such that its velocity varies according to vx=βx-2n, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x is given by

  1. -2nβ2x-2n-1
  2. -2nβ2x-4n-1
  3. -2nβ2x-2n+1
  4. -2nβ2x-4n+1

Solution

According to the question
a=vdvdx=vddxβx​-2n
=-2nβx-2n-1 βx-2n
=-2nβ2x-4n-1

Asked in: NEET 2015 (Phase 1)

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