A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is $\mathrm{S}_1$ and that covered in the first 20 seconds is $\mathrm{S}_2$ then :

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Aicharya · Accepted Answer

$\mathrm{s}=\frac{1}{2} \mathrm{at}^2$ $\begin{aligned} & \frac{\mathrm{s}_2}{\mathrm{~s}_1}=\left(\frac{20}{10}ight)^2=4 \ & \mathrm{~s}_2=4 \mathrm{~s}_1 \end{aligned}$

A particle starts its motion from rest under the action of a constant force. If the distance covered in…

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