A particle starts executing simple harmonic motion from one extreme position. If $\mathrm{a}, \mathrm{b}$…

A particle starts executing simple harmonic motion from one extreme position. If $\mathrm{a}, \mathrm{b}$ and $c$ are the displacements of the particle from the mean position at the ends of three successive seconds, the frequency of simple harmonic motion is
  1. $\frac{1}{\pi} \operatorname{Cos}^{-1}\left[\frac{\mathrm{a}+\mathrm{b}}{\mathrm{c}}\right]$
  2. $\frac{1}{2 \pi} \cos ^{-1}\left[\frac{b+c}{2 a}\right]$
  3. $\frac{1}{2 \pi} \operatorname{Cos}^{-1}\left[\frac{\mathrm{a}+\mathrm{c}}{2 \mathrm{~b}}\right]$
  4. $\frac{1}{2 \pi} \operatorname{Cos}^{-1}\left[\frac{\mathrm{a}+\mathrm{b}}{2 \mathrm{c}}\right]$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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