A particle starting from the origin $(0,0)$ moves in a straight line in the $(x, y)$ plane. Its coordinates at a later time are $(\sqrt{3}, 3)$. The path of the particle makes with the $x$-axis an angle of:

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Aicharya · Accepted Answer

Particle starts moving from $(0, 0)$ and goes till $(\sqrt{3}, 3)$. So total displacement along x axis is $\sqrt{3}$ unites and along y axis is 3 units. We know that: $\begin{aligned} & \Rightarrow \tan (\theta)=\frac{y}{x} \ & \Rightarrow \tan (\theta)=\frac{3}{\sqrt{3}} \ & \Rightarrow \tan (\theta)=\sqrt{3} \ & \Rightarrow \theta=\frac{\pi}{3}=60^{\circ} \end{aligned}$

A particle starting from the origin $(0,0)$ moves in a straight line in the $(x, y)$ plane. Its coordinates…

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