A particle of mass $M$ starting from rest undergoes uniform acceleration. If the speed acquired in time $T$…
A particle of mass $M$ starting from rest undergoes uniform acceleration. If the speed acquired in time $T$ is $v$, the power delivered to the particle is
$\frac{\mathrm{Mv}^2}{\mathrm{~T}}$
$\frac{1}{2} \frac{\mathrm{Mv}^2}{\mathrm{~T}^2}$
$\frac{\mathrm{Mv}^2}{\mathrm{~T}^2}$
$\frac{1}{2} \frac{\mathrm{Mv}^2}{\mathrm{~T}}$
Solution
The kinetic energy of particle $=\frac{1}{2} \mathrm{Mv}^2$
$\begin{aligned}
\text { Power } & =\frac{\text { Energy }}{\text { Time }} \\
\mathrm{P} & =\frac{1}{2} \frac{\mathrm{Mv}^2}{\mathrm{~T}}
\end{aligned}$