A particle of mass ' $m$ ' performs uniform circular motion of radius ' $r$ ' with linear speed ' $v$ '…
- $12 \%$
- $14 \%$
- $44 \%$
- $144 \%$
Solution
After $20 \%$ increase in all $\mathrm{m}, \mathrm{v}$ and r , $\begin{array}{ll} & \mathrm{F}_2=\frac{1.2 \mathrm{~m} \times(1.2 \mathrm{v})^2}{1.2 \mathrm{r}}=1.44 \frac{\mathrm{mv}^2}{\mathrm{r}}=1.44 \mathrm{~F}_1 \\ \therefore \quad & \mathrm{~F}_2-\mathrm{F}_1=0.44 \mathrm{~F}_1 \\ \therefore \quad & \frac{\mathrm{~F}_2-\mathrm{F}_1}{\mathrm{~F}_1} \times 100=44 \% \end{array}$ i.e., increase in force required is $44 \%$ .
Asked in: MHT CET 2024 (10 May Shift 2)
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