A particle of mass m projected with a velocity u making an angle of 30 ° with the horizontal. The magnitude…

A particle of mass m projected with a velocity u making an angle of 30° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height h is :
  1. 316mu3g
  2. 32mu2g
  3. mu32g
  4.  zero

Solution

Angular momentum at maximum height will be, L=mucosθh, where h=maximum height

Therefore, L=mucosθ×u2sin2θ2g

=mu32g×32×122=3mu316g

Asked in: JEE Main 2024 (30 Jan Shift 1)

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