A particle of mass m is projected with a velocity v = k V e ( k < 1 ) from the surface of the earth ( V e…

A particle of mass m is projected with a velocity v=kVe (k<1) from the surface of the earth (Ve= escape velocity). The maximum height above the surface reached by the particle is___
  1. Rk1-k2
  2. Rk1+k2
  3. Rk21-k2
  4. R2k1+k

Solution

v=kVe(k<1)

12mv2-GMmR=0-GMmR+h

12mk2×2GMR-GMmR=-GMmR+h     Ve=2GMR 

GMmk2R=-GMm1R+h-1R

k2R=hR(R+h)1+Rh=1k2

Rh=1k2-1

h=RK21-k2

Asked in: NEET 2021

Practice more Gravitation questions on Aicharya