A particle of mass ' m ' is projected with a velocity ' u ' ' making an angle ' θ ' with the…

A particle of mass 'm' is projected with a velocity 'u' ' making an angle 'θ' with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height is
  1. 0
  2. musin2⁡θcos⁡θ2g
  3. 2mu2cos2⁡θsin⁡θg
  4. mu3sin2⁡θcos⁡θ2g

Solution

Angular momentum of the particle, L=mvr⊥=mvh

⇒L=mucosθ×u2sin2θ2g

⇒L=mu3sin2θcosθ2g

Asked in: AP EAMCET 2021 (19 Aug Shift 2)

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