A particle of mass m is moving along a trajectory given by x = x 0 + a   c o s ω 1 t y = y 0 + b   s i n ω 2 t The torque, acting on the particle about the origin, at t = 0 is:

Question

A particle of mass m is moving along a trajectory given by x = x 0 + a &#160; c o s &#969; 1 t y = y 0 + b &#160; s i n &#969; 2 t The torque, acting on the particle about the origin, at t = 0 is:

Aicharya · Accepted Answer

x = x 0 + a c o s ω 1 t y = y 0 + b s i n ω 2 t a x = - a ω 1 2 c o s ω 1 t a y = - b ω 2 2 s i n ω 2 t At t = 0 , F → = m a → = - a ω 1 2 i ^ And r → = x 0 + a i ^ + y 0 j ^ Torque, τ = r → × F → τ = x 0 + a i ^ + y 0 j ^ × - a ω 1 2 i ^ = m y 0 a ω 1 2 k ^

A particle of mass m is moving along a trajectory given by x = x 0 + a   c o s ω 1 t y = y 0 + b…

Solution

A particle of mass m is moving along a trajectory given by x = x 0 + a &#160; c o s &#969; 1 t y = y 0 + b…

Solution

A particle of mass m is moving along a trajectory given by x = x 0 + a c o s ω 1 t y = y 0 + b…