A particle of mass $\mathrm{m}$ is at rest at the origin at time $\mathrm{t}=0$. It is subjected to a force…

A particle of mass $\mathrm{m}$ is at rest at the origin at time $\mathrm{t}=0$. It is subjected to a force $\mathrm{F}(\mathrm{t})=\mathrm{F}_0 \mathrm{e}^{-\mathrm{bt}}$ in the $x$ direction. Its speed $v(t)$ is depicted by which of the following curves?




Solution

$\mathrm{F}=\mathrm{F}_0 \mathrm{e}^{-\mathrm{bt}}$ $\Rightarrow \quad \mathrm{a}=\frac{\mathrm{F}}{\mathrm{m}}=\frac{\mathrm{F}_0}{\mathrm{~m}} \mathrm{e}^{-\mathrm{bt}}$ $\Rightarrow \quad \frac{\mathrm{dv}}{\mathrm{dt}}=\frac{\mathrm{F}_0}{\mathrm{~m}} \mathrm{e}^{-\mathrm{bt}}$ $\quad\int \mathrm{dv}=\int_0^{\mathrm{t}} \frac{\mathrm{F}}{\mathrm{m}} \mathrm{e}^{-\mathrm{bt}} \mathrm{dt}$ $\Rightarrow v=\frac{F}{m}\left[\frac{-1}{b}\right]\left[e^{-b t}\right]_0^t$ $\Rightarrow \quad v=\frac{F}{m b}\left[e^{-b t}\right]$ $v=0 \text { at } t=0$ and $\quad v \rightarrow \frac{F}{m b}$ as $t \rightarrow \infty$ So, velocity increases continuously and attains a maximum value of $v=\frac{F}{m b}$ as $t \rightarrow \infty$.

Asked in: JEE Main 2012 (Offline)

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