A particle of mass 500   g is moving in a straight line with velocity v = b x 5 2 . The work done by…

A particle of mass 500 g is moving in a straight line with velocity v=bx52. The work done by the net force during its displacement from x=0 to x=4 m is  (Take b=0.25  m-32s-1).
  1. 2 J
  2. 4 J
  3. 8 J
  4. 16 J

Solution

According to the work-energy theorem, work done by all forces will be is equal to the change in kinetic energy.

Wall=ΔK  

=12mb2x25-x15  =12×0.5×116×45=16 J  

Asked in: JEE Main 2022 (29 Jun Shift 1)

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