A particle of charge - q and mass m moves in a circle of radius r around an infinitely long line charge of linear density + λ . Then time period will be given as: (Consider k as Coulomb's constant)

Question

Aicharya · Accepted Answer

Attractive electrostatic force due to line charge on the charged particle will provide the required centripetal force. Therefore,
$q (\frac{2 k λ}{r}) = m ω^{2} r$
^{$\Rightarrow ω^{2} = \frac{2 k λ q}{m r^{2}}$}
^{$\Rightarrow {(\frac{2 π}{T})}^{2} = \frac{2 k λ q}{m r^{2}}$}
^{$\Rightarrow T = 2 π r \sqrt{\frac{m}{2 k λ q}}$}

A particle of charge - q and mass m moves in a circle of radius r around an infinitely long line charge of…

Solution