A particle moving with kinetic energy E has de Broglie wavelength λ . If energy Δ E is added to…

A particle moving with kinetic energy E has de Broglie wavelength λ . If energy ΔE is added to its energy, the wavelength become λ2 . Value of ΔE, is:
  1. E
  2. 4E
  3. 3E
  4. 2E

Solution

λ=h2KEm⇒λ∝1KE
λλ2=KEfKEi
4KEi=KEf
⇒ΔE=4KEi-KEi=3KE=3E

Asked in: JEE Main 2020 (09 Jan Shift 1)

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