A particle moving in $\mathrm{x}-\mathrm{y}$ plane starts from the origin at $\mathrm{t}=0$ with an initial velocity $(-\hat{\mathrm{i}}+\hat{\mathrm{j}}) \mathrm{ms}^{-1}$ and undergoes an acceleration of $(6 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}) \mathrm{ms}^{-2}$. It's displacement after $2…

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A particle moving in $\mathrm{x}-\mathrm{y}$ plane starts from the origin at $\mathrm{t}=0$ with an initial velocity $(-\hat{\mathrm{i}}+\hat{\mathrm{j}}) \mathrm{ms}^{-1}$ and undergoes an acceleration of $(6 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}) \mathrm{ms}^{-2}$. It's displacement after $2 \mathrm{~s}$ is

Aicharya · Accepted Answer

We have $\begin{aligned} & \mathrm{x}=(-1 	imes 2)+\frac{1}{2} 	imes 6 	imes 2^2=-2+12=10 \mathrm{~m} \ & \mathrm{y}=(1 	imes 2)+\frac{1}{2} 	imes 4 	imes 2^2=2+8=10 \mathrm{~m} \ & 	ext { So, }\left.\overrightarrow{\mathrm{r}}ight|_{\mathrm{t}=2 \mathrm{sec}}=10 \hat{\mathrm{i}}+10 \hat{\mathrm{j}} \ & |\overrightarrow{\mathrm{r}}|=\sqrt{10^2+10^2}=10 \sqrt{2} \mathrm{~m} \ & =14.14 \mathrm{~m}\end{aligned}$

A particle moving in $\mathrm{x}-\mathrm{y}$ plane starts from the origin at $\mathrm{t}=0$ with an initial…

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