A particle moves along a circular path with decreasing speed. Hence
A particle moves along a circular path with decreasing speed. Hence
its resultant acceleration is towards the centre.
its angular momentum remains constant.
the direction of angular momentum remains constant.
it moves in a spiral path with decreasing radius.
Solution
A particle moves along a circular path with speed, then the angular momentum is given by
$\overrightarrow{\mathrm{L}}=\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{p}}=\overrightarrow{\mathrm{r}} \times \mathrm{m} \overrightarrow{\mathrm{v}}$
When the speed v decrease, the magnitude of of angular momentum decreases. But the direction of angular momentum remains constant.