A particle moves along a circular path of radius $r$ with uniform speed $v$. The angle described by a…
A particle moves along a circular path of radius $r$ with uniform speed $v$. The angle described by a particle in one second is
$v r^2$
$\frac{v^2}{r}$
$\frac{r}{v}$
$\frac{v}{r}$
Solution
Here, a particle moves along a circular path of radius $r$ with uniform speed $v$.
Thus, the angular velocity is:
$\omega=\frac{v}{r}$
The angle described by the radius vector is:
$\theta=\omega t$
For $t=1 \mathrm{~s}$,
$\theta=\omega=\frac{v}{r}$