A particle located at $x=0$ at time $t=0$, starts moving along the positive $x$-direction with a velocity ' $v$ ' that varies as $v=\alpha \sqrt{x}$. The displacement of the particle varies with time as

Question

Aicharya · Accepted Answer

$\frac{\mathrm{d} x}{\mathrm{dt}}=\alpha \int \frac{\mathrm{dx}}{\sqrt{\mathrm{x}}}=\int \alpha \mathrm{dt} \Rightarrow \mathrm{x} \alpha \mathrm{t}^2$

A particle located at $x=0$ at time $t=0$, starts moving along the positive $x$-direction with a velocity '…

Solution