A particle is revolving in anticlockwise sense along the circumference of a circle of radius 'r' with linear…
A particle is revolving in anticlockwise sense along the circumference of a circle of radius 'r' with linear velocity 'v', then the angle between ' $\mathrm{v}^{\prime}$ and angular velocity '$\omega^{\prime}$ will be
$180^{\circ}$
$90^{\circ}$
$45^{\circ}$
$0^{\circ}$
Solution
1. The linear velocity $\vec{v}$ of a particle moving in a circular path is always tangential to the circle at any point on its path.
2. The angular velocity $\vec{\omega}$ is directed along the axis of rotation, which is perpendicular to the plane of the circle (according to the right-hand rule, since the particle is revolving in the anticlockwise sense, $\vec{\omega}$ points outward from the plane).
Thus, the angle between $\vec{v}$ (tangential) and $\vec{\omega}$ (perpendicular to the plane) is always 90 degrees.