A particle is projected with velocity v 0 along x -axis. A damping force is acting on the particle which is…

A particle is projected with velocity v0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e. ma=-αx2. The distance at which the particle stops:
  1. 2v03α13
  2. 3mv022α13
  3. 3v022α12
  4. 2v023α12

Solution

F=-αx2

ma=-αx2

a=-αx2 m

vdvdx=-αmx2

v00vdv=0x-αmx2dx

v22v00=-αmx330x

-v022=-αmx33

x=3mv022α13

Asked in: JEE Main 2021 (24 Feb Shift 2)

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